CBSE BOARD X, asked by adnanali4135, 11 months ago

(SecA+tanA-1)(secA-tanA +1)=2 tanA

Answers

Answered by pansumantarkm
2

Explanation:

(secA + tanA - 1)(secA - tanA +1)

= {sec A +(tanA - 1)}{secA - (tanA - 1)}

= (secA)² - (tanA - 1)²

= sec²A - (tan²A - 2tanA +1)

= sec²A - tan²A + 2tanA - 1

= 1 + 2tanA - 1. [ sec²A - tan²A = 1]

= 2 tanA (Hence Proved)

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