Question

(secA-tanA)^=1-sinA/1+sinA

Answer 1

1-sinA/1+sinA=(secA-tanA)²


L.H.S

1-sinA/1+sinA


Rationalising the denominator



1-sinA (1-SinA) /1+sinA(1-SinA)


(1-SinA)²/ 1² -(Sin²A)


(1-SinA)²/ 1 -(Sin²A)




(1-SinA)² /Cos² A


[ 1 -Sin²A = cos²A]


(1-SinA/CosA)²



(1/CosA-SinA/CosA)²


(SecA-tanA)²



L.H S = R H.S

hope you help !!!!

Answer 2

$1 \div \cos(x ) - \sin(x) \div \cos( x) \\ 1 - \sin(x) \div \cos(x) \\ 1 - \sin(x) \div 1 + \sin {}^{2} ( {x}^{} )$