Question

(secA + tanA) (1 - sinA)​

Answer 1

Answer:

I don't know maths so excuse me

Step-by-step explanation:

sorry Rashmi

Answer 2

Step-by-step explanation:

to answer this question.

1 Answer

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answered Nov 10, 2017 by priya12 (-12,635 points)

tanA + secA - 1 / tanA - secA + 1 = 1 + sinA / cosA

LHS = tanA + secA -1 / tanA - secA + 1

= tanA + secA + tan2A - sec2A / tanA - secA + 1

as tan2A + 1 = sec2A

= tanA + secA +(tanA + secA)(tanA - secA)/ tanA - secA + 1

= tanA + secA( 1 + tanA - secA) / tanA - secA + 1

=tanA + secA

= sinA / cosA + 1/cosA

= sinA + 1 / cosA