Question

(secA + tanA)(1-sinA)= ?

Answer 1

Answer:

this is the answer for the question

Answer 2

$\sec(a) + \tan(a) (1 - \sin(a) \\ = \sec(a) + \tan(a) - \sec(a) \tan(a) \times \sin(a ) \\ = ( \frac{1}{ \cos(a) } ) + \tan(a) - \tan(a) - ( \frac{ {sin}^{2}(a) }{ \cos(a) }$

$= ( \frac{1}{ \cos(a) } ) - ( \frac{ {sin}^{2}(a) }{ \cos(a) } ) \\ = ( \frac{1 - {sin}^{2} a}{ \cos(a) } )$

$= \frac{ {cos}^{2} a}{ \cos(a) } \\ = \cos(a)$