Question

(secA+tanA)(1-sinA)=​

Answer 1

Answer:

(secA+tanA) (1-sinA)

(secA+tanA) (cos)

=(secAcosA+tanAcosA)

={(1/cosA) ×cosA +( sinA/cosA) ×cosA}

=(1+sinA) <-(ans)

#i put the second bracket in order to make u understand cosA will be cut with other cosA...second bracket is not needed in the sum....the first bracket is enough.