(secA + tanA) (1-sinA)=?
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We need to find value of (secA+tanA)(1−sinA)
Putting the values of secA and tanA as
secA=
cosA
1
tanA=
cosA
sinA
(
cosA
1
+
cosA
sinA
)(1−sinA)
=
cosA
1+sinA
(1−sinA)
=
cosA
1−sin
2
A
=
cosA
cos
2
A
.... (As 1−sin
2
A=cos
2
A)
=cosA
Hope helpful.....
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