Math, asked by imjipark05, 11 hours ago

(SecA+tanA) (1-sinA) =?

Answers

Answered by bagkakali

1

Answer:

(sec A+tan A)(1-sinA)

=sec A+tan A-secA.sinA-tanA.sinA

=sec A+tanA-sinA/cosA-tanA.sinA

=secA+tanA-tanA-tanA.sinA

=secA-tanA.sinA

=1/cosA-sinA.sinA/cosA

=1/cosA-sin^2A/cosA

=(1-sin^2A)/cosA

=cos^2A/cosA

=cosA

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