Math, asked by amuda963852, 1 year ago

(secA+tanA) (1-sinA) =.....a) secA...b) sinA...c) cisecA..d) cosA..​

Answers

Answered by psh234
1

Answer:

The answer is d)cosA

Step-by-step explanation:

consider LHS

(secA+cosA) (1-sinA)

=1/cosA +sinA/cosA

=1+sinA/cosA(1-sinA)

=1+sinA-sinA-sin^2A/cosA

=1-sin^2A/cosA

=cos^2A/cosA

=cosA

Answered by IshikaSunilSharma
1

Answer:

solution refers to the attached file dear

(d) cos A

Attachments:
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