(secA+tanA) (1-sinA) =.....a) secA...b) sinA...c) cisecA..d) cosA..
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Answered by
1
Answer:
The answer is d)cosA
Step-by-step explanation:
consider LHS
(secA+cosA) (1-sinA)
=1/cosA +sinA/cosA
=1+sinA/cosA(1-sinA)
=1+sinA-sinA-sin^2A/cosA
=1-sin^2A/cosA
=cos^2A/cosA
=cosA
Answered by
1
Answer:
solution refers to the attached file dear
(d) cos A
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