Question

(secA+tanA) (1-sinA)=(a) secA (b) sinA (c) cosecA (d) cosA​

Answer 1

Answer:

hope it helps u........

Answer 2

Answer:

option d [cosA]

Step-by-step explanation:

[1/cosA+sinA/cosA] [1-sinA]

[1+sinA][1-sinA]/cosA

1-sinA²/cosA

WKT     [ sin²A+cos²A=1]

cos²A/cosA

cosA

∴(secA+tanA) (1-sinA)=cosA