(secA+tanA)(1-sinA)=cosA
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Answered by
0
Answer:
(1/cosA+sinA/cosA)(1-sinA)
(1+sinA)/cosA×(1-sinA)
(1-sin^2A)/cosA
cos^2A/cosA
cosA
Answered by
1
Answer:
cosA =cosA
Explanation:
(1/cosA+sinA/cosA) (1-sinA)
(1+sinA whole upon cosA ) (1-sinA)
1-sin^2A/cosA [ a^2- b^2 =(a+b) (a-b)]
cos^2A/CosA [1-sin^2A = cos^2A]
cosA
LHS=RHS
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