Math, asked by Effat, 1 year ago

(secA+tanA)(1-sinA)=cosA

Answers

Answered by choki60

0

(1/cosA+sinA/cosA)×(1-sinA) ,1-sinsq.A/cosA,cossqA/cosA=cosA

Answered by AJAYMAHICH

1

LHS =(secA+tanA)(1-sinA)

=(1/cosA+sinA/cosA)(1-sinA)

=(1+sinA/cosA)(1-sinA)

=(1+sinA)(1-sinA)/cosA

=(1-sin2A)/cosA

=cos2A/cosA

=cosA

LHS=RHS

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