Question

(secA + tanA) (1-sinA) = cosA


plz slove this​

Answer 1

we know cos = 1/sec and tan = sin/cos

L. H. S

( 1/cos + sin/cos) (1-sin)

(1+sin/cos) (1-sin)

1-sin^2/cos

Using,

(a-b) (a+b) = a^2 - b^2

cos^2/cos = cos

Answer 2

(1/cosA +sinA/cosA)(1-sinA)

(1+sinA)/cosA)(1-sinA)

(1-sinA^2)/cosA

cosA^2/cosA

cosA

L.H.S=R.H.S