Question

(secA+tanA)(1-sinA) is​

Answer 1

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(secA + tanA) (1-sinA)

Putting values of secA and tanA

= (1/cosA + sinA/cosA) (1-sinA)

now taking LCM,

= [(1+sinA)(1-sinA)]/cosA

= (1-sin²A)/cos A

putting sin²A + cos ²A = 1

= cos²A/ cosA

= cos A

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