Question

(secA+tanA) (1-sinA)
simplify it​

Answer 1

$\sec(a) + \tan(a) (1 - \sin(a)) \\ = ( \frac{1}{ \cos(a) } + \frac{ \sin(a) }{ \cos(a) } )(1 - \sin(a) ) \\ = \frac{(1 + \sin(a) )}{ \cos(a) } + (1 - \sin(a)) \\ = \frac{(1 + \sin(a)) (1 - \sin(a)) }{ \cos(a) } \\ = \frac{(1 - { \sin}^{2}a)}{ \cos(a) } \\ = \frac{ { \cos(a) }^{ 2} }{ \cos(a) } \\ = \cos(a) (ans).$

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Answer 2

Answer :-

Cos A

Solution step by step is in a image.

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