Question

(secA + tanA -1/tanA - secA +1)^2=?​

Answer 1

Step-by-step explanation:

(secA + tanA - 1/tanA - secA +1)²

sec A = Hypotenuse/Base = H/B

tan A = perpendicula/Base = P/B

Now equation will be.

(H/B + P/B - B/P - H/B)²

(P/B - B/P)²----------------(a-b)²=a²-2ab+b²

(P/B)² - 2 + (B/P)²-------Answer

(:I hope it will help you:)