Question

(secA-tanA)^2=1-sinA/1+sinA​

Answer 1

Answer:

Above photo will give you your answer

Answer 2

Answer:

Step-by-step explanation:

(secA-tanA)^2=1-sin/1+sin

(secA-tanA)^2=1-sin/1+sin*1-sin/1+sin                        rationalise it

(secA-tanA)^2=1+sin^2-2sin/1-sin^2

(secA-tanA)^2=1+sin^2-2sin/cos^2

(secA-tanA)^2=1/cos^2 +sin^2/cos^2-2sin/cos^2      

(secA-tanA)^2=sec^2+tan^2-2sesctanA

(secA-tanA)^2=(secA-tanA)^2

LHS=RHS

PROVED

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