(secA-tanA)² = 1-sinA/1+sinA
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Answered by
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Answer:
(1/cosA-sinA/cosA)^2
(1-sinA)^2/cosA^2
=(1-sinA)^2/(1-cosA^2)
=(1-sinA)(1-sinA)/(1-sinA)(1+sinA)
=(1-sinA)/(1+sinA)
hence proved
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