Question

(secA-tanA)² = 1-sinA/1+sinA​

Answer 1

1-sinA/1+sinA=(secA-tanA)²

RHS

1-sinA/1+sinA

Rationalising the denominator

1-sinA (1-SinA) /1+sinA(1-SinA)

(1-SinA)²/ 1² -(Sin²A)

(1-SinA)²/ 1 -(Sin²A)

(1-SinA)² /Cos² A

[ 1 -Sin²A = cos²A]

(1-SinA/CosA)²

(1/CosA-SinA/CosA)²

(SecA-tanA)²

L.H S = R H.S

Answer 2

HEYA USER ❤️

REFER TO THE ATTACHMENT ❣️