Question

(secA-tanA)²=1-sinA/1+sinA​
prove L.H.S=R.H.S

Answer 1

Step-by-step explanation:

thank u my dear friend,, again I remember trigonometry because of u... thank. u... and the answer and license is correct.. if this helps u thank me.. and plz follow me dear...

Answer 2

Answer:

$(secA { - tanA})^{2} \\ \\ = ( \frac{1}{cosA} - \frac{sinA}{cosA} ) ^{2} \\ \\ = \frac{( {1 - sinA})^{2} }{ {cos}^{2} A} \\ \\ = \frac{( {1 - sinA})^{2} }{1 - {sin}^{2} A} \\ \\ = \frac{1 - sinA}{1 + sinA}$