Question

secA+tanA =3 then secA =​

Answer 1

Answer:-

Given:-

sec A + tan A = 3 -- equation (1).

We know that,

sec² A - tan² A = 1

using a² - b² = (a + b)(a - b) we get,

→ (sec A + tan A)(sec A - tan A) = 1

Putting the value of sec A + tan A we get,

→ (3) * (sec A - tan A) = 1

→ sec A - tan A = 1/3 -- equation (2)

Add equations (1) & (2).

→ sec A + tan A + sec A - tan A = 3 + 1/3

→ 2sec A = (9 + 1) / 3

→ sec A = 10/3 * (1/2)

→ sec A = 5/3

Hence, the value of sec A is 5/3.