Math, asked by sakshibhasme, 1 year ago

secA+tanA=cosA÷1-sinA

Answers

Answered by adarshshrivastoxcs0i
0

SecA + tanA = 1/cosA + sinA/cosA

= (1+sinA)/cosA

= (1+sinA)(1-sinA)/cosA(1-sinA)

= (1-sin^2 A)/cosA(1-sinA)

= Cos^2 A/cosA(1-sinA)

= cosA/1-sinA


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