Question

secA+tanA=P find sinA

Answer 1

Solution:-

given :-

secA+tanA=P find sinA

1/cosA+ sinA/cosA= p

(1+sinA) / p.cosA

sinA = p.cosA -1

Answer 2

Answer:

Given :

sec A + tan A = p

I am replacing p by ' k '

sec A + tan A = k

We know :

sec A = H / B   & tan A = P / B

H / B + P / B =  k / 1

H + P / B =  k / 1

So , B = 1

H + P = k

P = k - H

From pythagoras theorem :

H² = P² + B²

H² = ( H - k )² + 1

H² = H² + k² - 2 H k + 1

2 H k = k² + 1

H = k² + 1 / 2 k

P = k - H

P = k² - 1 / 2 k

Now write k = p we have :

Base = 1

Perpendicular P = P² - 1 / 2 P

Hypotenuse H = P² + 1 / 2 P

Value of sin A =  P / H

sin A =  P² - 1 / 2 P / P² + 1 / 2 P

sin A = P² - 1 / P² + 1

Therefore , we got value .