Question

SecA+TanA= P prove that p^2-1/p^2+1 = sinA​

Answer 1

$\frac{ {(sec(A) + \tan(A))}^{2} - 1 }{{(sec(A) + \tan(A))}^{2} + 1} \\ \frac{ {(sec(A) + \tan(A))}^{2} - { \sec }^{2} A + {tan}^{2} A}{{(sec(A) + \tan(A))}^{2} + { \sec }^{2} A - {tan}^{2} A} \\ \frac{{ \sec A \: }+ {tan \: A (2tanA)}}{{ \sec A }+ {tan \: A(2secA)}} \\ = sin \:A$