Question

secA + tanA=p then cosA =?

Answer 1

sec+tan=p
sec=p-tan
sec square = p sq. + tan sq. - 2tan
sec sq. - tan sq. =p sq. - 2 tan

1= p sq. -2tan....

hence. tan = p sq. -1 /2......
now I think u can do the rest by urself.
hope it help

Answer 2

The answer is given below :

Given that,

secA + tanA = p .....(i)

We know that,

sec²A - tan²A = 1

=> (secA + tanA)(secA - tanA) = 1

=> p × (secA - tanA) = 1

=> secA - tanA = 1/p .....(ii)

Now, adding (i) and (ii), we get

2 secA = p + 1/p

=> secA = (p² + 1)/2p

=> cosA = 2p/(p² + 1)

So, cosA = 2p/(p² + 1) [Ans.]

Thank you for your question.