secA+tanA=p yhen find the value of secA-tanA?
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SecA + tanA = P
we know that,
(sec^A - tan^A) = (sec^A + tan^A)(sec^A - tan^A)
so,
(sec^A + tan^A)(sec^A - tan^A)
P(sec^A - tan^A) = 1
(sec^A - tan^A) = 1/P
Therefore, (sec^A - tan^A) = 1/P
#BeBrainly
we know that,
(sec^A - tan^A) = (sec^A + tan^A)(sec^A - tan^A)
so,
(sec^A + tan^A)(sec^A - tan^A)
P(sec^A - tan^A) = 1
(sec^A - tan^A) = 1/P
Therefore, (sec^A - tan^A) = 1/P
#BeBrainly
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