(secA+tanA/secA-tamA)
Answers
Answered by
1
Answer:
Step-by-step explanation:
Sec A - Tan A / Sec A + Tan A × Sec A - Tan A / Sec A - Tan A
= (Sec A - Tan A)² / (Sec A + Tan A)(Sec A - Tan A)
= (Sec A - Tan A)² / Sec²A - Tan²A
= Sec²A + Tan²A - 2 (Sec A × Tan A)
= 1 + Tan²A + Tan²A - 2 (Sec A × Tan A)
= 1 - 2 (Sec A × Tan A) + 2 Tan²A
hope this will help
please mark it as the brainliest answer
Answered by
3
Step-by-step explanation:
secA+tanA / secA-tanA
-1 / 1
answer is -1
hope this help you...
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