Math, asked by syedpasha000786, 1 year ago

(secA+tanA/secA-tamA)​

Answers

Answered by meenu102004
1

Answer:

Step-by-step explanation:

Sec A - Tan A / Sec A + Tan A  ×  Sec A - Tan A / Sec A - Tan A

= (Sec A - Tan A)² / (Sec A + Tan A)(Sec A - Tan A)

= (Sec A - Tan A)² / Sec²A - Tan²A

= Sec²A + Tan²A - 2 (Sec A × Tan A)

= 1 + Tan²A + Tan²A - 2 (Sec A × Tan A)

= 1 - 2 (Sec A × Tan A) + 2 Tan²A

hope this will help

please mark it as the brainliest answer

Answered by saibanipanigrahy
3

Step-by-step explanation:

secA+tanA / secA-tanA

-1 / 1

answer is -1

hope this help you...

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