Math, asked by edoc008, 1 year ago

secA-tanA/secA+tanA = 1-2secAtanA+2tan^2A

Answers

Answered by todinson255

0

Answer:

Step-by-step explanation:

secA-tanA/secA+tanA

=ratinalize

=then we get

=sec^2A+tan^2A-2tanAsecA/1

=1+2tan^2-2secAtanA

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