Math, asked by cranu8535, 9 months ago

secA+tanA/secA-tanA=1+2secAtanA+2tan²A

Answers

Answered by devinichenametla

2

Step-by-step explanation:

secA+tanA=1/secA-tanA

so,secA+tanA/secA-tanA=(secA+tanA)²

=sec²A+tan²A+2secAtanA

=1+2secAtanA+2tan²A

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