Question

secA-tanA/secA+tanA=cos2a/(1+sin2a)

Answer 1

Answer:

LHS=RHS

Step-by-step explanation:

LHS= SecA-TanA/SecA+TanA

=1/CosA-SinA/CosA/1/CosA+SinA/CosA

=1-SinA/CosA/1+SinA/CosA

=1-SinA/CosA*CosA/1+SinA

(CosA and Cos A cancels)

=1-SinA/1+SinA

Multiplying conjugate of 1-SinA (i.e. 1+SinA)

=1-SinA/1+SinA*1+SinA/1+SinA

=1^2-Sin^2A/(1+SinA)^2

=Cos^2A/1+Sin^2A

=RHS

=Hence proved

Hope it helps you.....