Question

secA +tanA/secA-tanA - secA -tanA /secA +tanA​

Answer 1

Answer:

0

2+2+2+ 2 + 2 + 2 = ?

२

3+3+ 3+ 3 + 3+3=

pls markbranilest

2

Answer 2

♣︎ Solution :

$\: \: \: \: \: \: : \implies \small{\frac{ \sec(x) + \tan(x) }{ \sec(x) - \tan(x) } - \frac{ \sec(x) - \tan(x) }{ \sec(x) + \tan(x) } }$

$\: \: \: \: \: \: : \implies \small{\frac{ { \big(\sec (x) + \tan(x) \big)}^{2} - {\big(\sec (x) - \tan(x) \big)}^{2}}{{\big(\sec (x) + \tan(x) \big)}^{}{\big(\sec (x) - \tan(x) \big)}^{}}}$

$\: \: \: \: \: \: : \implies \small{ \frac{4 \tan(x) \sec(x) }{ { \sec}^{2}(x) - { \tan}^{2} (x) } }$

$\: \: \: \: \: \: : \implies \bf4 \sec(x) \tan(x)$

♣︎ Some Important Identities :

$\: \: \: \: \: \: \: \longmapsto {(a + b)}^{2} - {(a - b)}^{2} = 4ab$

$\: \: \: \: \: \: \: \longmapsto { \sec}^{2} (x) - { \tan }^{2} (x) = 1$