Question

secA-tanA=x then find the value of secA-tanaA

​

Answer 1

Step-by-step explanation:

$\sec \theta + \tan \theta= x \\ = > { (\sec\theta + \tan\theta )}^{2} = {x}^{2} \\ = > { \sec }^{2} \theta + { \tan}^{2} \theta + 2 \sec\theta.\tan\theta = {x}^{2} \\ = > { \sec }^{2} \theta + { \tan}^{2} \theta + 2 \sec\theta.\tan\theta - 4 \sec\theta.\tan\theta= {x}^{2} - 4 \sec\theta.\tan\theta \\ = > { \sec }^{2} \theta + { \tan}^{2} \theta - 2 \sec\theta.\tan\theta = {x}^{2} - 4 \sec\theta.\tan\theta \\ = > { (\sec\theta - \tan\theta )}^{2} = {x}^{2} - 4 \sec\theta.\tan\theta \\ = >\sec\theta - \tan\theta = \sqrt{{x}^{2} - 4 \sec\theta.\tan\theta}$