secA-tanA=x then prove that sec A + tan A = 1/x
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Answered by
5
heya friends..
it's too easy...
secA-tanA=x (given )-----1)
1/tanA-tanB=1/p
And ...by using rationalising process ..
1/secA-tanA×secA+tanA/secA+tanA=1/p
=>secA+tanA/sec²A-tan²A=1/p
=>secA+tanA/1 =1/p{•°•sec²A-tan²A=1}
secA+tanA.=1/p prooved here..
hope it helps you.
#Rajukumar
it's too easy...
secA-tanA=x (given )-----1)
1/tanA-tanB=1/p
And ...by using rationalising process ..
1/secA-tanA×secA+tanA/secA+tanA=1/p
=>secA+tanA/sec²A-tan²A=1/p
=>secA+tanA/1 =1/p{•°•sec²A-tan²A=1}
secA+tanA.=1/p prooved here..
hope it helps you.
#Rajukumar
Answered by
2
after that transfer x to another side
u will get ur answer
u will get ur answer
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