Question

(SecA+Tand)(1-Sind) = ?​

Answer 1

Answer:

$(secx + tanx)(1 - sinx) \\ = ( \frac{1 + sinx}{cosx} )(1 - sinx) \\ = \frac{1 - {sin}^{2} x}{cosx} \\ = \frac{ {cos}^{2}x }{cosx} \\ = cosx$