Question

Secant A (1-sine A) (secant A + tangent A ) =1​

Answer 1

L.H.S=secA(1−sinA)(secA+tanA)=(secA−

cosA

sinA

)(secA+tanA)

=(secA−tanA)(secA+tanA)

=sec

2

A−tan

2

A

Putting if tan

2

A+1=sec

2

A−

we get L.H.S=1+tan

2

A−tan

2

A=1

⇒L.H.S=R.H.S

Answer 2

Answer:

I hope it is helpful to you