Question

Secant theta +tan theta =4, then secant theta -tan theta

Answer 1

$we \: know \\ { \sec}^{2} \theta - { \tan }^{2} \theta = 1 \\ ( \sec \theta + \tan \theta)( \sec \theta - \tan \theta) = 1 \\ \sec \theta - \tan \theta = \frac{1}{\sec \theta + \tan \theta} = \frac{1}{4}$