Math, asked by rushanknaik2005, 1 year ago

(seco-1) (coseco-1) = 1

Answers

Answered by rreexx123

0

Step-by-step explanation:

LHS

=(secx-1) (cosecx-1)

=secx*cosec x - secx - cosec x +1

= 1/sin x*cosx - (sinx+cosx)/sinx*cosx +1

=(1-sinx-cosx)/sinx.cosx +1

=(1-sinx-cosx + sinx. cosx)/sinx.cosx

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