secO - tanO = √ 1 - sinO / 1 + sinO
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√[(1+sina)/(1-sina)]
= √[(1+sina)(1+sina)/(1-sina)(1+sina)]
=√[(1+sina)²/(1-sin²a)]
=√[(1+sina)²/cos²a]
=(1+sina)/cosa
=1/cosa. +sina/cosa
=seca+tana
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