Question

• (seco-tano)2=1-sino/1+sino​

Answer 1

Answer:

(sec theta -tan theta) ^2=1+sin theta/1-sin theta

(1/cos theta-cos theta/sin theta)^2=(1-sin)(1-sin) /cos^2 theta

(1-sin theta) (1-sin theta) /(1-sin theta) (1+sin theta)

1-sin theta/1+sin theta=1+sin theta/1+sin theta

LHS=RHS

Answer 2

Answer:

(sin theta_tan theta) 2= 1+ sin theta 1_ sin theta

( 1/ cos theta_ cos theta / sin theta)( 2= 1 _ sin )(1_ sin theta)/ 2cos theta

( 1_ sin theta )( 1 _sin theta)/( 1+ sin theta) 1+ sin theta)

LHS = RHS

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