Question

secøcotø=cosecø
prove that​

Answer 1

LHS:-

$sec \theta . cot \theta$

$= \dfrac{1}{cos \theta} . \dfrac{1}{tan \theta}$

$= \dfrac{H}{A} . \dfrac{A}{O}$

$= \dfrac{H}{O}$

$= \dfrac{1}{sin \theta}$

$= cosec \theta$

RHS:-

$cosec \theta$.

So, LHS = RHS.