second derivative of acosmx + bsinmx
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I can't understand what's this. Check your question. I think it's a trash question. But If I see it with more concentration, I can understand something about math.
Both the words end with mx. That's common in both. If we leave that We get-- CosA and SinB - which relates TRIGONOMETRY.
Apologise me if answer is wrong
Both the words end with mx. That's common in both. If we leave that We get-- CosA and SinB - which relates TRIGONOMETRY.
Apologise me if answer is wrong
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