Question

second derivative of Y = tan^2 (3x+2)​

Answer 1

Answer:

d\dxtan)²(3x) =6sec)²tan(3x)²

Step-by-step explanation:

In order to differentiate this function, we have to apply the chain rule twice :

d\dx tan[f(x)]=sec²[f(x)]f(x)

d\dx[tan(x)]n-1sec²x

so applying these two rules we get :

d\dxtan²(3x) =2tan(3x)sec²(3x) (3)

=6sec²(3x) tan(3x)