Question

second equation of motion without graph​

Answer 1

hey dear. ..here is your answer

S=ut +1/2 at power 2

Distance =area under v -t graph

= area of OABC

= area of OABC + triangle ABD

=u.t +1/2(OC) .(v-u)

S =ut +1/2 (at). t

therefore S=ut +1/2 at power 2

hope it helps uh...

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