Question

Second excitation potential for He+ ion is (1) 12.09 eV (2) 48.36 eV (3) 3.4 eV (4) 51 eV

Answer 1

Answer:

For a hydrogen atom like system the energy for n

th

level is given by E

n

=

n

2

−13.6Z

2

eV

So the ground state energy will be E

1

=

1

−13.6Z

2

eV

and for the state n=2 the energy is E

2

=

4

−13.6Z

2

eV

So the excitation energy foe this state will be E

2

−E

1

=10.2Z

2

eV

as it is given to be 40.8eV so Z

2

=4 or Z=2

So the energy in ground state will be E

1

=−54.4eV

so the inonization energy will be −(−54.4eV)=54.4eV

Answer 2

Explanation:

this is answer to your physics question which have been wrongly answered