Second ionisation energy of cr is higher than vn and mn why?
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When Cr⁺ is formed the specie became more stable by acquiring the configuration [Ar] 3d⁵, 4s⁰ Thus its second ionization energy is higher.
It can by better understand by considering the electronic configuration of Cr.
The electronic configuration of Cr is,
Cr = [Ar] 3d⁵, 4s¹
It form ion by removing the one electron of 4s. Thus it form Cr⁺.
When Cr⁺ is formed the electronic configuration became,
Cr = [Ar] 3d⁵, 4s⁰
Here we can see there are 5 electrons in 3d which is the more stable state and required highest energy to remove the second electron from Cr. Thus its second ionization energy is higher.
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