Second negative term of AP √108,√75,√48....... is ?
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Answer:
the answer you will get is -2√3
Step-by-step explanation:
after solving these you can find that the ap is
√108=6√3
√75=5√3
√48=4√3
so the first term is a=6√3
difference d=(-√3)
so after putting the term value is
a~n= a+(n-1)d
0=6√3 + (n-1)(-√3)
n-1=6
n=7
so 7th term is 0
a~8 =0-√3=-√3
a~9 = -√3-√3= (-2√3)
so9th term is second negative number of ap series (-2√3)
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