Biology, asked by shree2002laxmi, 10 months ago

Second,
(Take it = 3.14.)
the side of a square sheet of metal is increasing at 3 centimetres per
minute. At what rate is the area increasing when the side is 10 cm long?
5. The radius of a circular soap bubble is increasing at the rate of 0.2 cm/s. Find
the rate of increase of its surface area when the radius is 7cm.​

Answers

Answered by PubgekgerGmailcom
1

Answer:

MATHS

The radius of a soap bubble is increasing at the rate of 0.2 cm/sec. At what rate the surface area of a bubble increasing when the radius is 7 cm and at what rate the volume of a bubble increasing when the radius is 5 cm ?

December 26, 2019avatar

Pari Yumnam

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ANSWER

Bubble is spherical.

(I)⇒ surface area =4πr

2

=5

Rate of change is given by :

dt

ds

=4π(2r)

dt

dr

at r=7cm

dt

dr

=0.2cm/se

dt

ds

=8×

7

22

×7×0.2

=8×22×

10

2

=

10

352

=35.2cm

2

/sec.

(II)Volume=v=

3

4

πr

3

Rate of change is :

dt

du

=

3

4

π(3r

2

)

dt

dr

=4πr

2

(

dt

dr

)

at r=5cm,

dt

dr

=0.2cm/sec

dt

dr

=4×

7

22

×25×0.2

=62.857cm

3

/sec.

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