Question

(Sect A+ tanA) (1- sin A)​

Answer 1

Answer:

Hola

Step-by-step explanation:

Here is ur best answer ....

And i have done it with thetha .. . u can replace with A ...

Answer 2

Answer:

⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇

➡ (sec A + tan A) (1 - sin A)

• sec ø = 1/cos ø
• tan ø = sin ø/cos ø

➡ (1/cos A + sin A/cos A) (1 - sin A)

➡ [ (1 + sin A) /cos A) ] (1 - sin A)

➡ [ (1 + sin A) (1 - sin A) /cos A ]

• (a + b) (a - b) = a² - b²

➡ (1 - sin² A) /cos A

• 1 - sin² ø = cos² ø

➡ cos² A/cos A

➡ cos A

Therefore, " (Sec A+ tanA) (1- sin A) = cos A "

⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆

Step-by-step explanation:

PLEASE MARK ME AS BRAINLIEST

✌✌✌✌