Math, asked by yuvika6717, 3 months ago

sectheta -tan theta =cosec thta -1/cosec theta +1​

Answers

Answered by mvandanamishra542
1

Answer:

LHS :

q(p

2

−1)

=(secθ+cosec θ)[(sinθ+cosθ)

2

−1]

=(

cosθ

1

+

sinθ

1

)(2sinθcosθ)

=(

sinθcosθ

sinθ+cosθ

)(2sinθcosθ)

=2(sinθ+cosθ)=2p = RHS

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