sectheta -tan theta =cosec thta -1/cosec theta +1
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1
Answer:
LHS :
q(p
2
−1)
=(secθ+cosec θ)[(sinθ+cosθ)
2
−1]
=(
cosθ
1
+
sinθ
1
)(2sinθcosθ)
=(
sinθcosθ
sinθ+cosθ
)(2sinθcosθ)
=2(sinθ+cosθ)=2p = RHS
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