Sectheta +tantheta=p find sintheta and tantheta
Answers
Answered by
2
Hey,,,,,,,,,
Sec¢+tan¢=p,,,,,,,,,,,,,,,,,,, 1)
And, sec^2¢-tan^2¢=1, we know. ------2)
Then divided 2)by 1)
it become, sec¢-tan¢=1/p. ,,,,,,,,, 3)
Now from 1) and 3) we get sec¢=1/2(p+1/p)
And tan¢=1/2(p+1/p)
Sin¢=tan¢/sec¢=1/2(p-1/p) /1/2p+1/p)
=(p^2-1)/(p^2+1).
Sec¢+tan¢=p,,,,,,,,,,,,,,,,,,, 1)
And, sec^2¢-tan^2¢=1, we know. ------2)
Then divided 2)by 1)
it become, sec¢-tan¢=1/p. ,,,,,,,,, 3)
Now from 1) and 3) we get sec¢=1/2(p+1/p)
And tan¢=1/2(p+1/p)
Sin¢=tan¢/sec¢=1/2(p-1/p) /1/2p+1/p)
=(p^2-1)/(p^2+1).
Similar questions