(secthetha+tanthetha).(secthetha-tanthetha)
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Answered by
1
heya..
(sec Q + tan Q) (sec Q - tan Q)
(sec Q)square -(tan Q) square =1...
here Q suppose to thetha....
hope it help...
(sec Q + tan Q) (sec Q - tan Q)
(sec Q)square -(tan Q) square =1...
here Q suppose to thetha....
hope it help...
Answered by
1
Answer is sec^2theta-tan^2theta
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